Sec 2 · Algebra · Deep Study

Understanding Algebra

This guide explains the why behind every rule — not just what to memorise, but how to think algebraically. Work through each section in order, study each worked example step by step, then test yourself with the checkpoint questions and reveal the answers to check your thinking.

5 sections Worked examples with steps Checkpoint questions Intuition-first explanations
1
Variables & Expressions
What letters mean and how expressions are built

Before algebra, every problem had to be solved with specific numbers. Algebra gave mathematicians a tool to describe any situation — by using a letter to stand for a number we don't know yet, or a number that can change.

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Why do we use variables?
Consider the question "what number, when you double it and add 3, gives 11?" You could guess and check — or you could write 2x + 3 = 11 and solve it in two steps. Variables let us generalise: the rule Perimeter = 4 × side works for every square, not just one with a specific side length. That power to generalise is the entire point of algebra.

Key Vocabulary

TermMeaningExample
VariableA letter representing an unknown or changing numberx, y, n
TermA single number, variable, or product of both5x, −3, 7xy
CoefficientThe number multiplying a variable in a termIn 5x, the coefficient is 5
Like termsTerms with the same variable(s) raised to the same exponents3x and −7x are like terms
ExpressionA combination of terms — no equals sign3x + 2y − 5
EquationTwo expressions linked by an equals sign3x + 5 = 14
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The Distributive Property: a(b + c) = ab + ac
Multiply the factor outside the brackets by every term inside. This is the single most-used rule in algebra.
Distributive Property
a(b + c) = ab + ac
Applies to any number of terms inside: a(b + c + d) = ab + ac + ad
★ Easy
Expanding brackets (distributive property)
Expand: (a) 3(2x − 5)    (b) −2(x + 4)
Show solution
1
Part (a) — identify the factor and each term

The factor outside is 3. Inside the brackets: +2x and −5.

3(2x − 5) = 3 × 2x + 3 × (−5)
2
Multiply each term
= 6x − 15
3
Part (b) — the factor is negative: −2

Be careful: a negative times a positive gives a negative; a negative times a negative gives a positive.

−2(x + 4) = −2 × x + (−2) × 4
4
Multiply each term
= −2x − 8
Answers: (a) 6x − 15    (b) −2x − 8
★★ Medium
Expand and simplify
Simplify: 4(x + 3) − 2(3x − 1)
Show solution
1
Expand the first bracket
4(x + 3) = 4x + 12
2
Expand the second bracket — careful with the negative

The minus sign in front of 2(3x − 1) means the entire second bracket is being subtracted.

−2(3x − 1) = −6x + 2
3
Write all terms together
4x + 12 − 6x + 2
4
Combine like terms
x terms: 4x − 6x = −2x
constants: 12 + 2 = 14
Result: −2x + 14
Answer: −2x + 14
✅ Checkpoint 1
a) In the expression 7x − 3y + 5, identify: the number of terms, the coefficient of x, and the coefficient of y.
b) Expand: 5(3x − 2)
c) Is 4x + 9 an expression or an equation? What about 4x + 9 = 0?

a) 3 terms. Coefficient of x is 7. Coefficient of y is −3 (the minus sign belongs to the term).

b) 5(3x − 2) = 5 × 3x + 5 × (−2) = 15x − 10

c) 4x + 9 is an expression — no equals sign. 4x + 9 = 0 is an equation — it has an equals sign making a statement about x.

2
Simplifying Expressions
Combining like terms and expanding brackets

Simplifying means writing an expression in its shortest, clearest form. The two main tools are: combining like terms, and expanding brackets with the distributive property.

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Why can you only combine like terms?
Think of terms as physical objects. 3 apples + 2 apples = 5 apples. But 3 apples + 2 oranges cannot be simplified — they are different things. In algebra, 3x and 2x are like terms (both "groups of x") and combine to 5x. But 3x and 2y are different variables — you cannot add them into a single term.
Like terms
Same variable & exponent — add/subtract coefficients
Expand then simplify
Distribute first, then collect like terms
Result check
Substitute a value to verify both forms are equal
⚠️
Distributing a negative sign is the most common error.
−3(x − 4) = −3x + 12, NOT −3x − 12.
Remember: negative × negative = positive. The −3 multiplies both the x and the −4.
★ Easy
Combining like terms
Simplify: 5x + 3y − 2x + 7 − y
Show solution
1
Group the like terms (rearrange)
(5x − 2x) + (3y − y) + 7
2
Combine each group
x terms: 5x − 2x = 3x
y terms: 3y − y = 2y
constants: 7
3
Write the result
3x + 2y + 7
Answer: 3x + 2y + 7
★★ Medium
Expand then simplify
Simplify: 2(3x + 1) − 4(x − 2)
Show solution
1
Expand the first bracket
2(3x + 1) = 6x + 2
2
Expand the second bracket — distribute −4
−4(x − 2) = −4x + 8   (−4 × −2 = +8)
3
Write all expanded terms
6x + 2 − 4x + 8
4
Combine like terms
x terms: 6x − 4x = 2x
constants: 2 + 8 = 10
Result: 2x + 10
Answer: 2x + 10
✅ Checkpoint 2
a) Simplify: 4a − 3b + 7 + 2a + b − 4
b) Expand and simplify: 3(2x − 5) + 4(x + 1)
c) A student writes −5(x − 3) = −5x − 15. Identify the error and give the correct answer.

a) Group: (4a + 2a) + (−3b + b) + (7 − 4) = 6a − 2b + 3

b) 3(2x − 5) = 6x − 15; 4(x + 1) = 4x + 4. Together: 6x − 15 + 4x + 4 = 10x − 11

c) Error: −5 × −3 should be +15, not −15. Correct answer: −5x + 15. (Negative times negative is positive.)

3
First-Degree Equations
Isolating the variable — the balance model

An equation is like a perfectly balanced scale. Both sides weigh the same because they are equal. Your job is to find the value of the unknown variable — and you do that by keeping the scale balanced at every step.

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The balance analogy:
If you have a balanced scale and you add 5 kg to one side, you must add 5 kg to the other side to keep it balanced. Same in algebra: whatever operation you apply to one side of the equation, you must apply the exact same operation to the other side. This is the golden rule that makes algebra work.
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The goal is always to isolate the variable. You want to get x (or whatever letter is used) alone on one side, with a plain number on the other side. That number is the solution.

Solving Procedure

  1. Expand any brackets using the distributive property
  2. Collect all variable terms on one side (add or subtract)
  3. Collect all constant terms on the other side
  4. Divide both sides by the coefficient of the variable
  5. Check your answer by substituting it back into the original equation
Equality Principle
If a = b, then a + c = b + c   and   a × c = b × c
The same operation on both sides preserves equality
★ Easy
Simple one-step equation
Solve: 3x + 5 = 14
Show solution
1
Subtract 5 from both sides
3x + 5 − 5 = 14 − 5
3x = 9
2
Divide both sides by 3
3x ÷ 3 = 9 ÷ 3
x = 3
3
Check: substitute x = 3 into the original
3(3) + 5 = 9 + 5 = 14 ✓
Answer: x = 3
★★ Medium
Equation with brackets on one side
Solve: 3(x − 2) = 2x + 7
Show solution
1
Expand the bracket on the left
3x − 6 = 2x + 7
2
Move variable terms to the left (subtract 2x from both sides)
3x − 2x − 6 = 7
x − 6 = 7
3
Move constant to the right (add 6 to both sides)
x = 7 + 6
x = 13
4
Check: substitute x = 13
Left: 3(13 − 2) = 3 × 11 = 33
Right: 2(13) + 7 = 26 + 7 = 33 ✓
Answer: x = 13
★★★ Hard
Equation with fractions — clear denominators first
Solve: x/3 + 1 = x/2 − 2
Show solution
1
Find the LCD of the denominators

Denominators are 3 and 2. LCD = 6. Multiply every term on both sides by 6.

2
Multiply every term by 6
6 × (x/3) + 6 × 1 = 6 × (x/2) − 6 × 2
2x + 6 = 3x − 12
3
Move variable terms to one side, constants to the other
6 + 12 = 3x − 2x
18 = x
4
Check: substitute x = 18 into the original
Left: 18/3 + 1 = 6 + 1 = 7
Right: 18/2 − 2 = 9 − 2 = 7 ✓
Answer: x = 18
🧠
Common trap — sign errors when moving terms:
When you move a term across the equals sign it changes sign. This is really just adding the opposite to both sides. For example: x − 5 = 3 → add 5 to both sides → x = 3 + 5 = 8. Students often write x = 3 − 5 — a sign flip error. Always think "what did I add/subtract to both sides?" rather than mechanically moving a term.
✅ Checkpoint 3
a) Solve: 5x − 3 = 22
b) Solve and check: 4(x + 2) = 3x + 11
c) Solve: x/4 + 3 = x/6 + 5  (Hint: LCD = 12)

a) 5x = 22 + 3 = 25 → x = 25 ÷ 5 = 5. Check: 5(5) − 3 = 22 ✓

b) Expand: 4x + 8 = 3x + 11 → 4x − 3x = 11 − 8 → x = 3. Check: 4(3+2) = 20 and 3(3)+11 = 20 ✓

c) Multiply by 12: 3x + 36 = 2x + 60 → x = 60 − 36 = 24. Check: 24/4 + 3 = 9 and 24/6 + 5 = 9 ✓

4
Inequalities
Like equations, with one crucial difference

An inequality is a statement that one expression is greater than, less than, or equal to another. You solve inequalities using exactly the same steps as equations — with one critical extra rule.

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Why does the inequality sign flip when you multiply or divide by a negative?
Picture the number line. We know 3 < 8. Now multiply both sides by −1: −3 and −8. On the number line, −3 is to the right of −8, so −3 > −8. The order reversed! Multiplying by a negative always reflects numbers across zero, swapping left and right — and therefore flipping the inequality direction.

Inequality Symbols

SymbolMeaningNumber line
<Strictly less than — the left side is smallerOpen circle, arrow pointing left
>Strictly greater than — the left side is largerOpen circle, arrow pointing right
Less than or equal to — includes the boundary valueClosed (filled) circle, arrow left
Greater than or equal to — includes the boundary valueClosed (filled) circle, arrow right
⚠️
The flip rule — never forget this:
When you multiply or divide both sides of an inequality by a negative number, the inequality sign must be flipped.
Example: −2x < 8  →  divide both sides by −2  →  x > −4 (sign flipped from < to >).
The Flip Rule
If −ax < b, then x > −b/a   (sign flips)
Only flips when multiplying or dividing by a negative — adding/subtracting never flips the sign
★ Easy
Simple inequality
Solve: 2x + 3 < 11
Show solution
1
Subtract 3 from both sides
2x + 3 − 3 < 11 − 3
2x < 8
2
Divide both sides by 2 (positive — no flip)
2x ÷ 2 < 8 ÷ 2
x < 4
3
Interpret the solution

The solution is all real numbers less than 4. On a number line: open circle at 4, arrow pointing left.

Answer: x < 4
★★ Medium
Inequality requiring a sign flip
Solve: 5 − 3x ≥ 14
Show solution
1
Subtract 5 from both sides
5 − 3x − 5 ≥ 14 − 5
−3x ≥ 9
2
Divide both sides by −3 — FLIP the sign

Dividing by a negative number: the ≥ becomes ≤.

−3x ÷ (−3) ≤ 9 ÷ (−3)
x ≤ −3
3
Verify with a test value (e.g. x = −5)
5 − 3(−5) = 5 + 15 = 20 ≥ 14 ✓ (works)
Test x = 0: 5 − 0 = 5 ≥ 14? No ✗ (correctly excluded)
Answer: x ≤ −3
✅ Checkpoint 4
a) Solve: 4x − 1 > 11
b) Solve: −2x + 6 ≤ 12  (watch the flip!)
c) A student solves −4x > 20 and writes x > −5. What did they do wrong? Give the correct answer.

a) 4x > 11 + 1 = 12 → x > 12 ÷ 4 = 3. (Divided by positive 4 — no flip.)

b) −2x ≤ 12 − 6 = 6 → divide by −2, flip sign: x −3.

c) The student divided by −4 to get −5, but forgot to flip the sign. Correct: x < −5. When you divide both sides by −4, the > must become <.

5
Word Problems
Translating sentences into equations

Word problems are where algebra meets the real world. The skill is not in the arithmetic — it is in the translation: reading a sentence and writing it as a mathematical equation.

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Algebra as a language:
Every sentence in a word problem contains mathematical clues. "Increased by" means addition. "Times" means multiplication. "Is" means equals. Once you learn to read these clues, translating a paragraph into an equation becomes straightforward — and then you already know how to solve the equation.
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5-step method for any word problem:
1. Read carefully — identify what is unknown and what information is given.
2. Define the variable — write "let x = ..." clearly.
3. Write an equation — translate the key sentence into algebra.
4. Solve the equation — use the steps from Section 3.
5. Answer in a full sentence — state what x represents, include units if needed.
Is / equals
"is" → =
More than / increased by
"more than" → +
Times / product of
"times" → ×

Common Translations

English phraseAlgebra
A number increased by 5x + 5
Three times a number3x
A number decreased by 7x − 7
Twice a number minus 42x − 4
Half of a numberx/2
The sum of two consecutive integersx + (x + 1)
★ Easy
Number problem
A number increased by 8 equals three times the number minus 4. Find the number.
Show solution
1
Define the variable
Let x = the unknown number
2
Translate: "a number increased by 8" = "three times the number minus 4"
x + 8 = 3x − 4
3
Solve — move variable terms left, constants right
x − 3x = −4 − 8
−2x = −12
x = 6
4
Check
Left: 6 + 8 = 14
Right: 3(6) − 4 = 18 − 4 = 14 ✓
Answer: The number is 6.
★★ Medium
Consecutive integers problem
The sum of three consecutive integers is 57. Find the three integers.
Show solution
1
Define the variable

Consecutive integers follow each other in order: 4, 5, 6 or −1, 0, 1, etc. If the first is x, the next is x+1, then x+2.

Let x = first integer
Then x+1 = second integer
And x+2 = third integer
2
Write the equation: their sum is 57
x + (x + 1) + (x + 2) = 57
3
Simplify and solve
3x + 3 = 57
3x = 54
x = 18
4
Find all three integers and check
x = 18, x+1 = 19, x+2 = 20
Check: 18 + 19 + 20 = 57 ✓
Answer: The three consecutive integers are 18, 19, and 20.
✅ Checkpoint 5
a) Five more than twice a number equals 23. Find the number.
b) The sum of two consecutive even integers is 46. Find the integers. (Hint: consecutive even integers differ by 2, so let them be x and x+2.)
c) Esmeralda is 3 years younger than her brother Emil. In 5 years, the sum of their ages will be 39. How old is Esmeralda now?

a) Let x = the number. Equation: 2x + 5 = 23 → 2x = 18 → x = 9. Check: 2(9)+5 = 23 ✓

b) Let x = first even integer. x + (x+2) = 46 → 2x + 2 = 46 → 2x = 44 → x = 22. The integers are 22 and 24. Check: 22 + 24 = 46 ✓

c) Let x = Esmeralda's current age, then Emil's age now = x + 3. In 5 years: (x+5) + (x+3+5) = 39 → 2x + 13 = 39 → 2x = 26 → x = 13. Esmeralda is currently 13 years old. Check: Emil is 16; in 5 years they are 18 and 21; 18 + 21 = 39 ✓