Kinematics

Cheat Sheet  ·  Physics Gr 11
Emil Oliversen
MOTION BASICS
Always define your + direction first. All signs follow from that choice.
displacement
Δd = d_f − d_i
velocity
v = Δd / Δt
acceleration
a = Δv / Δt
speed
scalar: distance / time
Distance = total path (scalar)
Displacement = net change in position (vector)
Speed uses distance · velocity uses displacement
VARIABLE KEY
SymbolMeaningUnit
ddisplacementm
v₀initial velocitym/s
vfinal velocitym/s
aaccelerationm/s²
ttimes
ggravity9.8 m/s²
UAM EQUATIONS (use only when a = constant)
Eq 1
v = v₀ + at
Eq 2
d = v₀t + ½at²
Eq 3
v² = v₀² + 2ad
Eq 4
d = ((v₀+v)/2)·t
Eq 5
d = vt − ½at²
Pick the equation that has your 3 known variables + 1 unknown. Eq 3 has no t — use when t is missing.
g = 9.8 m/s² downward
If up is +: use a = −9.8 m/s²
If down is +: use a = +9.8 m/s²
CHOOSING AN EQUATION
Missing variableBest equation
t is unknownEq 3 (v² = v₀²+2ad)
v is unknownEq 2 (d = v₀t+½at²)
a is unknownEq 4 (d = avg·v·t)
d is unknownEq 1 (v = v₀+at)
MOTION GRAPHS
GraphSlope =Area =
d-tvelocity
v-taccelerationdisplacement
a-tjerk (rare)Δv
  • Straight d-t line → constant velocity
  • Curved d-t line → accelerating
  • Horizontal v-t line → constant velocity (a = 0)
  • Slope down on v-t → deceleration
  • Area below x-axis on v-t → negative displacement
PROJECTILE MOTION
Horizontal and vertical are independent. Time links them.
aₓ
0 (no horizontal force)
vₓ
constant = v₀ cos θ
x range
x = vₓ · t
aᵧ
−9.8 m/s² (if up is +)
vᵧ₀
v₀ sin θ
vᵧ at time t
vᵧ₀ − g·t
At peak height: vᵧ = 0 (but vₓ remains unchanged)
COMMON MISTAKES
  • Forgetting direction sign (+/−)
  • Using total distance instead of displacement for velocity
  • Mixing horizontal and vertical in projectile problems
  • Using UAM equations when a is NOT constant
  • Wrong sign for g (check: is up your + direction?)
  • Forgetting to find time before finding range in projectile
QUICK EXAMPLE — FREE FALL
Ball dropped from rest, falls 20 m:
v² = v₀² + 2ad
v² = 0 + 2(9.8)(20) = 392
v = √392 ≈ 19.8 m/s

v = v₀ + at
t = v/a = 19.8/9.8 ≈ 2.02 s
QUICK EXAMPLE — PROJECTILE
Horizontal launch at 12 m/s from 20 m cliff:
Vertical: 20 = ½(9.8)t² → t ≈ 2.02 s
Horizontal: x = 12 × 2.02 ≈ 24.2 m
PROJECTILE STRATEGY
  • Split v₀ into vₓ = v₀cosθ and vᵧ₀ = v₀sinθ
  • Use vertical equations to find time of flight
  • Use t to find horizontal range: x = vₓ·t
  • At peak: vᵧ = 0 → use to find max height